Jacare
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acabaram-se as torradas
acabaram-se as torradas
Eu sei que o pessoal já não pode ver torradas à frente! [
]
Na realidade esse problema apareceu depois de ter visto o filme "21" e de ter lido um livro onde se faz algumas referencias a John von Neumann e à teoria do jogo.
Pequisei na net e fui parar à wiki e aos supostos autores do problema "The Monty Hall": Marilyn vos Savant
Mais abaixo dei com um problema chamado ""Two boys" problem", alterei o texto para torradas a fim de minimizar as pesquisas no Google... e tentei dar uma lógica semelhante.
Like the Monty Hall problem, the "two boys" or "second-sibling" problem predates Ask Marilyn, but generated controversy in the column,[18] first appearing there in 1991-92 in the context of baby beagles:
A shopkeeper says she has two new baby beagles to show you, but she doesn't know whether they're male, female, or a pair. You tell her that you want only a male, and she telephones the fellow who's giving them a bath. "Is at least one a male?" she asks him. "Yes!" she informs you with a smile. What is the probability that the other one is a male?
—Stephen I. Geller, Pasadena, California
When vos Savant replied "One out of three" readers[citation needed] wrote to argue that the odds were fifty-fifty. In a follow-up, she defended her answer, observing that "If we could shake a pair of puppies out of a cup the way we do dice, there are four ways they could land", in three of which at least one is male, but in only one of which both are male. See Boy or Girl paradox for solution details.
The problem re-emerged in 1996-97 with two cases juxtaposed:
Say that a woman and a man (who are unrelated) each has two children. We know that at least one of the woman's children is a boy and that the man's oldest child is a boy. Can you explain why the chances that the woman has two boys do not equal the chances that the man has two boys? My algebra teacher insists that the probability is greater that the man has two boys, but I think the chances may be the same. What do you think?
Vos Savant agreed with the algebra teacher, writing that the chances are only 1 out of 3 that the woman has two boys, but 1 out of 2 that the man has two boys. Readers argued for 1 out of 2 in both cases, prompting multiple follow-ups. Finally vos Savant started a survey, calling on women readers with exactly two children and at least one boy to tell her the sex of both children. With almost eighteen thousand responses, the results showed 35.9% (a little over 1 in 3) with two boys.
acabaram-se as torradas
Eu sei que o pessoal já não pode ver torradas à frente! [
]Na realidade esse problema apareceu depois de ter visto o filme "21" e de ter lido um livro onde se faz algumas referencias a John von Neumann e à teoria do jogo.
Pequisei na net e fui parar à wiki e aos supostos autores do problema "The Monty Hall": Marilyn vos Savant
Mais abaixo dei com um problema chamado ""Two boys" problem", alterei o texto para torradas a fim de minimizar as pesquisas no Google... e tentei dar uma lógica semelhante.
Like the Monty Hall problem, the "two boys" or "second-sibling" problem predates Ask Marilyn, but generated controversy in the column,[18] first appearing there in 1991-92 in the context of baby beagles:
A shopkeeper says she has two new baby beagles to show you, but she doesn't know whether they're male, female, or a pair. You tell her that you want only a male, and she telephones the fellow who's giving them a bath. "Is at least one a male?" she asks him. "Yes!" she informs you with a smile. What is the probability that the other one is a male?
—Stephen I. Geller, Pasadena, California
When vos Savant replied "One out of three" readers[citation needed] wrote to argue that the odds were fifty-fifty. In a follow-up, she defended her answer, observing that "If we could shake a pair of puppies out of a cup the way we do dice, there are four ways they could land", in three of which at least one is male, but in only one of which both are male. See Boy or Girl paradox for solution details.
The problem re-emerged in 1996-97 with two cases juxtaposed:
Say that a woman and a man (who are unrelated) each has two children. We know that at least one of the woman's children is a boy and that the man's oldest child is a boy. Can you explain why the chances that the woman has two boys do not equal the chances that the man has two boys? My algebra teacher insists that the probability is greater that the man has two boys, but I think the chances may be the same. What do you think?
Vos Savant agreed with the algebra teacher, writing that the chances are only 1 out of 3 that the woman has two boys, but 1 out of 2 that the man has two boys. Readers argued for 1 out of 2 in both cases, prompting multiple follow-ups. Finally vos Savant started a survey, calling on women readers with exactly two children and at least one boy to tell her the sex of both children. With almost eighteen thousand responses, the results showed 35.9% (a little over 1 in 3) with two boys.
Última edição:
] queria só que alguém respondesse à seguinte questão:
] Eu nunca disse que estava mal formulado! Apenas digo que a resposta à maneira como ele está formulado é 50% [
]
]